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9 October, 21:20

The length of a rectangle is 6 yd longer than its width. if the perimeter of the rectangle is 44 yd, find its area.

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  1. 10 October, 00:12
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    Let's call the length L and the width w.

    perimeter = 2L + 2w

    44 = 2L + 2w

    the length is 6 yards longer than the width. so L = w + 6.

    plug this into the equation. 44 = 2 (w+6) + 2w

    44 = 2w + 12 + 2w

    44 = 4w + 12

    32 = 4w

    w = 8

    L = w + 6

    L = 8 + 6

    L = 14

    area = Lw

    area = 8 (14)

    area = 112 yd²
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