What is the surface area of a regular pentagonal prism with side length 8, altitue 20 and apothem approximately 5.5

The surface area of the pentagonal prism is given by:

SA=2[area of the pentagonal sides]+5[area of rectangle sides]

Area of pentagonal side will be given by:

Area=5/2 sa

where;

side, s=8

apothem, a=5.5

hence;

Area=5/2*8*5.5=110 sq units

Area of rectangular side will be:

Area=length*width

=20*8=160 sq units

therefore the surface area (SA) will be:

SA=110*2+5*160

=1,020 sq. units