If 5+20*2^ (2-3x) = 10*2^ (-2x) + 5, what is the value of x?

a - 3

b - 2

c 2

d 3

Step 1: get rid of the + 5 on both sides.

Step 2: divide by 10 on both sides

Then you have: 2*2^ (2-3x) = 2^ (-2x)

The factor 2 on the left can be brought into the exponent because you're simply multiplying with 2 more ...

2^ (1+2-3x) = 2^ (-2x)

Now you can equate the exponents:

3-3x = - 2x = > 3 = - 2x+3x = > x=3

so d is your answer.