Ask Question
26 March, 05:31

The roots of the equation are 3 + 8i and 3 - 8i.

What is the value of c?

x2 - 6x + c = 0

c = [1]

Answers (1)
  1. P
    26 March, 07:15
    0
    Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;

    taking x=3+8i and substituting it in our equation we get:

    (3+8i) ^2-6 (3+8i) + c=0

    -55+48i-18-48i+c=0

    collecting the like terms we get:

    -55-18+48i-48i+c=0

    -73+c=0

    c=73

    the answer is c=73
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The roots of the equation are 3 + 8i and 3 - 8i. What is the value of c? x2 - 6x + c = 0 c = [1] ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers
Sign In
Ask Question