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26 October, 04:46

What method most efficient to use to solve x^2+4x+3=0

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  1. 26 October, 05:16
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    My recommendation would be to factor ...

    x² + 4x + 3 = 0 factor the left side into two binomials

    (x + 3) (x + 1) = 0 set each of these binomials equal to zero and solve

    x + 3 = 0 Implies x = - 3

    x + 1 = 0 implies x = - 1
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