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26 December, 13:13

Find The vertex of this parabola y=4x^2+8x+1?

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  1. 26 December, 14:42
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    Y=4x^2+8x+1

    =4 (x^2+2x) + 1

    =4 (x+1) ^2 - 3

    The vertex is (-1, - 3)
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