If x and y are two nonnegative numbers and the sum of twice the first (x) and three times the second (y) is 60, find x so that the product of the first and cube of the second is a maximum.

If we translate the word problems to mathematical equation,

2x + 3y = 60

The second equation is,

P = xy³

From the first equation, we get the value of y in terms of x.

y = (60 - 2x) / 3

Then, substitute the expression of y to the second equation,

P = x (60-2x) / 3

P = (60x - 2x²) / 3 = 20x - 2x²/3

We derive the equation and equate the derivative to zero.

dP/dx = 0 = 20 - 4x/3

The value of x from the equation is 15.

Hence, the value of x for the value of the second expression to be maximum is equal to 15.