5 pennies, 3 dimes and 4 quarters are placed in a bag. what is the probability of selecting a quarter and then another quarter, given the first coin is not returned to the back after it is drawn? A. 2/11 B. 1/11 C. 1/22 D. 5/33

5+3+4 = 12 total coins

4 are quarters so first selection = 4/12 reduces to 1/3

after taking a coin out there would be 11 coins left and 3 quarters left

so 2nd selection would be 3/11

now multiply 3/11 x 1/3 = 3/33 which reduces to 1/11

B. 1/11 is the correct answer