The sum of three consecutive odd integers is 18 less than five times the middle number. Find the three integers.

Let us assume the first odd integer to be = x

Then

The consecutive middle odd integer = x + 2

The third consecutive odd integer = x + 4

So we can now write the equation as

x + x + 2 + x + 4 = 5 (x + 2) - 18

3x + 6 = 5x + 10 - 18

3x + 6 = 5x - 8

3x - 5x = - 8 - 6

- 2x = - 14

2x = 14

x = 14/2

= 7

So the first odd integer is 7

The second consecutive odd integer = (x + 2)

= (7 + 2)

= 9

The third consecutive odd integer = (x + 4)

= 7 + 4)

= 11

So the three consecutive odd integers are 7, 9, 11.