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24 April, 06:38

Solving system of equations y=3x+7, y=-4x+21

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Answers (2)
  1. 24 April, 07:49
    0
    The technique you would use for this is substitution since both equations are in y=mx+b form.

    3x+7=-4x+21

    now solve.

    subtract 4 on both sides

    7x+7=21

    then subtract 7 on both sides.

    7x=14

    then divide 7 on both sides

    x=2

    now, solve for y by plugging in to the first equation:

    y=3x+7

    y=3 (2) + 7

    y=13

    The solution set is (2,13)

    to check if this is correct you plug in x and y to the second equation

    y=-4x+21

    13=-4 (2) = 21

    13=13

    The solution set is (2,13)
  2. 24 April, 08:08
    0
    Since both equations are set equal to y, you can set the equations equal to each other and solve for x.

    3x + 7 = - 4x + 21

    Add 4x to both sides

    7x + 7 = 21

    Subtract 7 from both sides

    7x = 14

    Divide both sides by 7

    x = 2

    Now plug 2 back in either equation and solve for y.

    y = 3 (2) + 7

    y = 13

    (2,13)
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