For each quadratic function, find the axis of symmetry of its graph. Y=x^2 + 4x-7 Y=2x^2+3x-4

First find the vertex

the x coordinate of the vertex is the axis of symmetry

the vertex of an equation in form

y=ax^2+bx+c is

-b/2a=x coordinate

y=1x^2+4x-7

vertex=-4/2=-2

axis of symmetry is x=-2

y=2x^2+3x-4

ertex=-3 / (2*2) = - 3/4

axis of symmetry is x=-3/4