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2 August, 22:06

A bag contains 4 green 4 red 2 blue crayons, what is the probability of random choosing 2 red crayons without replacement

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  1. 3 August, 00:49
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    10 crayons in all.

    P (red) = 4/10 or 2/5

    P (2nd red) = 3/9 = 1/3 since there are only 9 crayons left from which to choose and only three of them are red (since we already pulled one).

    2/5 x 1/3 = 2/15 = P (2 red) with no replacement.
  2. 3 August, 01:17
    0
    If there are 10 crayons in a bag with 4 green, 4 red and 2 blue you have:

    4 chances out of 10 to get a green crayon, 4 chances out of 10 to get a red crayon and 2 chances out of 10 to get a blue one.

    On the first try, you have 4 chances out of 10 to get a red crayon.

    If you take this crayon out of the bag, it means that there are 9 crayons remaining with just three red crayon.

    Then, you have 3 out of 9 chances to get a red crayon on the second try.

    In order to know the probability to get a red crayon each try, we have to multiply each probability:

    4/10 * 3/9 = 2/90

    12/90 = 2/15

    So you have 2 chance out of 15 to get 2 red crayons in a row
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