Sara leaves home at 7am traveling at a rate of 45 mi/h. her son discovers that she has forgotten her briefcase and starts out to catch up with her. her son leaves at 7:30 am traveling at a rate of 55 mi/h. At what time will he over take his mother?

Sara 45 mph

Son 55 mph

Sara 07:00

Son 07:30

Difference in time = 00:30 = > 0.50 hours

Sara will have covered 22.50 miles Son starts

catch up distance = 22.50 miles

catch up speed = 55 - 45

catch up speed = 10 mph

Catchup time = catchup distance/catch up speed

catch up time = 2.25

catch up time = 2.25 hours

They will meet at 9:55 am mph