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25 June, 21:40

I need o fine the length and the width of the rectangle that haves the area 9in and the perimeter

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  1. 25 June, 23:12
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    The perimeter = (2 lengths) + (2 widths) = 12

    (1 length) + (1 width) = 6

    Area = (length) x (width)

    So you need two numbers that add to 6 and multiply to 9.

    How about 3 and 3?

    Area = 3 x 3 = 9

    Perimeter = 3 + 3 + 3 + 3 = 12

    It works, and your rectangle is actually a square!
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