Which quadratic function has a leading coefficient of 2 and a constant term of - 3?

f (x) = 2x^3 - 3

f (x) = - 3x^2 - 3x + 2

f (x) = - 3x^3 + 2

f (x) = 2x^2 + 3x - 3

Question

Mathematics

Haven

18 September, 21:16

Which quadratic function has a leading coefficient of 2 and a constant term of - 3?

f (x) = 2x^3 - 3

f (x) = - 3x^2 - 3x + 2

f (x) = - 3x^3 + 2

f (x) = 2x^2 + 3x - 3

+3

Answers (1)

Know the Answer?

Keegan Mccall · Answer 1

Quadatic means 2nd degree, means highest exponent of placeholder is 2

leading coefient is the number that is in front of the highest power x

constant term is the one that doesn't have an x witht it

quadratic

2nd and last fn are quadratic

leading coefient of 2 is first and last fn

constant term is - 3 for first and last fn

answer is last function

Which quadratic function has a leading coefficient of 2 and a constant term of - 3?f (x) = 2x^3 - 3f (x) = - 3x^2 - 3x + 2f (x) = - 3x^3 + 2f (x) = 2x^2 + 3x - 3

Which quadratic function has a leading coefficient of 2 and a constant term of - 3?

f (x) = 2x^3 - 3

f (x) = - 3x^2 - 3x + 2

f (x) = - 3x^3 + 2

f (x) = 2x^2 + 3x - 3