A chemist needs 90 milliliters of a 25% solution but has only 16% and 43% solutions available

Question

Mathematics

Jaeden Solis

23 February, 00:49

A chemist needs 90 milliliters of a 25% solution but has only 16% and 43% solutions available

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Answers (1)

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London Barron · Answer 1

Let f be amount of 43% and s be amount of 16% ...

s+f=90, f=90-s

(.16s+.43f) / 90=.25 using f found above we get:

(.16s+.43 (90-s)) / 90=.25

.16s+38.7-.43s=22.5

-.27s=-16.2

s=60, and since f=90-s, f=30

So the chemist will need to mix 60ml of 16% solution with 30ml of 43% solution to create 90ml of a 25% solution.