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27 January, 15:53

If in a triangle ABC, a-25, b=16, c=9 then tan (A/2) is?

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  1. 27 January, 17:21
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    We have the following givens:

    a=25

    b=16

    c=9

    We can make use of the Laws of Cosines in solving the angle A such as:

    cos A = (b²+c²-a²) / 2bc

    cos A = ((16) ²+9² - (25) ²) / 1*16*9

    A=180°

    tan (A/2) = tan (180/2)
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