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18 March, 12:19

A solution containing 30% insecticide is to be mixed with a solution containing 50% insecticide to make 200 L of a solutions containing 42% insecticide. How much of each solution should be used?

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  1. 18 March, 15:31
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    Let x L of solution 1 is used

    and 2nd solution is (200-x) L

    According to question,

    30% of x + 50% of (200-x) = 42% of 200L

    0.3x + 0.5 (200-x) = 84

    0.3x - 0.5x + 100 = 84

    0.2x = 16

    x=80

    Therfore 80L of solution 1 and 120L of solution 2 is mixed.
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