The letters of the alphabet are written on flashcards and dropped into a bag. A flashcard is randomly selected, kept out of the bag, and then another flashcard is randomly selected. which product gives the probability that both cards have a vowel (a, e, i, o, or u) written on them? A. 5/26*4/26 B. 5/26*4/25 C. 5/26*5/25 D. 5/26 * 5/26.

First of all, as I told you a little while ago, here is the formula

that solves ALL probability problems. Memorize this:

Probability =

(number of different successful possibilities)

divided by

(total number of all possibilities).

How many cards are in the bag at the beginning?

One with each letter of the alphabet. That's 26.

So the total number of different possible results on the

first draw is 26.

How many of them are 'successful'?

A 'successful' card is one with a vowel (a, e, i, o, or u). That's 5.

So the probability of pulling a vowel the first time is 5/26.

Now, we're looking for the probability of pulling TWO vowels, without

replacing the first one. So what's the situation after the first one?

If the first one is successful, then when you reach into the bag for

the second draw, there are only 25 total cards in the bag, and

only 4 vowels are left. So the probability of drawing a vowel the

second time is 4/25.

The first one was 5/26.

The second one was 4/25.

The probability of both of them happening just like that is

(5/26) x (4/25).

That looks like choice ' B ' to me.