In USA Today (Sept. 5, 1996), the results of a survey involving the use of sleepwear while traveling were listed as follows: Male Female Total Underwear 0.220 0.024 0.244 Nightgown 0.002 0.180 0.182 Nothing 0.160 0.018 0.178 Pajamas 0.102 0.073 0.175 T-shirt 0.046 0.088 0.134 Other 0.084 0.003 0.087 (a) What is the probability that a traveler is a female who sleeps in the nude? (b) What is the probability that a traveler is male? (c) Assuming the traveler is male, what is the probability that he sleeps in pajamas? (d) What is the probability that a traveler is male if the traveler sleeps in pajamas or a T-shirt?

Question

Mathematics

Holden Bernard

12 October, 21:33

In USA Today (Sept. 5, 1996), the results of a survey involving the use of sleepwear while traveling were listed as follows: Male Female Total Underwear 0.220 0.024 0.244 Nightgown 0.002 0.180 0.182 Nothing 0.160 0.018 0.178 Pajamas 0.102 0.073 0.175 T-shirt 0.046 0.088 0.134 Other 0.084 0.003 0.087 (a) What is the probability that a traveler is a female who sleeps in the nude? (b) What is the probability that a traveler is male? (c) Assuming the traveler is male, what is the probability that he sleeps in pajamas? (d) What is the probability that a traveler is male if the traveler sleeps in pajamas or a T-shirt?

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Answers (1)

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Averi · Answer 1

A) 0.018/1 = 0.018

b) Probability of Male in survey is 0.614. Therefore the asked probability is

0.614/1=0.614.

c) Now we are dividing with probability that person is Male.

0.102/0.614=0.166.

d) Probability that person sleeps in either T-shirt or pajamas is 0.175+0.134=0.309

Probability that male sleeps in pajamas or T-shirt

is 0.102+0.046=0.148

Final answer is:

0.148/0.166=0.479