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4 October, 07:29

Consider circle H with a 3 centimeter radius. If the length of minor arc RS is

5/2π, what is the measure of ∠RST? Assume that chords RS and TS are congruent.

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  1. 4 October, 11:10
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    Given:

    Radius = 3 cm

    length of minor arc = 5/2π

    length of the minor arc = 2 π r (x/360°)

    5/2π = 2 π r (x/360°)

    5/2 * 3.14 = 2 * 3.14 * 3 (x/360°)

    5/6.28 = 18.84 (x/360°)

    6.28 (5/6.28) = 6.28 (18.84) (x/360°)

    5 * 360° = 118.32x

    1800 / 118.32 = x

    15.21 = x
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