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23 April, 21:05

If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?

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  1. 24 April, 00:58
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    Y=kx is the direct variation equation

    First plug in the x, y values given to find K

    18=k (5)

    18/5=k

    3.6 = k

    Use the k and write a new equation.

    y=3.6x

    Plug in the x value to solve for y.

    y = 3.6 (11)

    y = 39.6
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