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18 August, 17:39

What is the probability that no 1s will be in the output for an input sequence of 10 digits?

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  1. 18 August, 18:38
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    The total numbers with 10 digits are 9*10*10*10*10*10*10*10*10*10 = 9 * (10^9)

    If you are restricted to use no 1s, the numbers are 8 * (9^9)

    Then, the probability is : numbers with no 1s / total numbers

    = 8 * (9^9) / [9 * (10^9) ] = 0.344
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