A cone-shaped container sits inside a larger cone. The inner cone has a height of 3 in. and a diameter of 6 in. The outer cone has the same diameter and is 15 in. tall. The extra space in the outer cone is filled with crushed ice to keep the contents of the inner cone cool.

What is the volume of the crushed ice?

volume of the cone = π r² h/3

volume of the small cone = 3.14 * (3in) ² * 3in/3

volume of the small cone = 3.14 * 9in² * 1in

volume of the small cone = 28.26 in³

volume of the big cone = 3.14 * (3in) ² * 15in/3

volume of the big cone = 3.14 * 9in² * 5in

volume of the big cone = 141.30 in³

volume of the crushed ice = 141.30 in³ - 28.26 in³ = 113.04 in³