Given y = 2x2 - 10x. Find all real values of x for which y = - 3.

First, plug in - 3 for the y value.

-3=2x²-10x

Then, add 3 to both sides.

0=2x²-10x+3

Use the quadratic equation to solve

(-b+-√b²-4ac) / 2a

You get 4.68 or 0.32

You still have to check your answer to see if there is an excluded value.

Both values check.