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6 November, 12:12

Complete the square to rewrite y = x^2 - 6x + 14 in vertex form. Then state whether the vertex is a maximum or minimum and give its coordinates.

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  1. 6 November, 14:43
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    Y=x²-6x+14

    y = (x²-2*3x + 3²-3²) + 14

    y = (x²-2*3x+3²) + 14-9

    y = (x-3) ²+5

    a=1

    p=3

    q=5

    a>0 ⇒ vertex is minimum

    V (p, q) ⇒ V (3; 5)

    Regards M. Y.
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