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16 May, 23:52

A baseball player swings and hits a pop fly straight up in the air to the catcher. The height of the baseball in meters t seconds after it is hit is given by the quadratic function h left parenthesis t right parenthesis equals negative 4.9t squared plus 14.7t plus 1h (t) = - 4.9t2+14.7t+1.

How long does it take for the baseball to reach its maximum height? What is the maximum height obtained by the baseball?

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  1. 17 May, 01:01
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    To solve for the time it reach the maximum height, you must solve the first derivative of the function and equate it to zero

    h (t) = - 4.9t^2 + 14.7t + 1

    dh / dt = - 9.8t + 14.7

    then equate to zero

    -9.8t + 14.7 = 0

    solve for t

    t = 1.5 s

    then the maximum height is when t = 1.5

    h (t) = - 4.9t^2 + 14.7t + 1

    h (1.5) = - 4.9 (1.5) ^2 + 14.7 (1.5) + 1

    h (1.5) = 12.025 m
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