The sum of the consecutive numbers is 111. What is the smallest of the three numbers?

Let

x = first consecutive number

x + 1 = second consecutive number

x + 2 = third consecutive number

The sum of these numbers are 111.

x + x + 1 + x + 2 = 111

3x = 111 - 1 - 2

3x = 108

x = 36

Therefore, the smallest number is 36 because other numbers are 37 and 38.

Answer=36 + 37 + 38 = 111 (36 is the smallest number)

In algebraic form it is x + x+1 + x+2 = 111 First you minus the 2 and the 1 to give you 108 and then divide that by 3 to give you x (36). That gives you the smallest of the consecutive numbers. Then add on the one on 36 to give 37 and another one to give 38.