Ask Question
18 December, 00:01

What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?

+1
Answers (1)
  1. 18 December, 01:54
    0
    Given:

    a1 = 8

    a9 = 48

    (48 - 8) / 8 = 40/8 = 5 difference of consecutive terms

    a (23) = 8 + [ (23-1) x 5]

    a (23) = 8 + (22x5)

    a (23) = 8 + 110

    a (23) = 118

    The 23rd term of the arithmetic sequence is 118.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers