Determine the range of the function f (x) = x^3-1 when the domain is {0,1,2}

The range will be ur y (or f (x) values ... the domain is ur x values. So it is just a matter of subbing.

f (x) = x^3 - 1 ... when domain (x) = 0

f (0) = 0^3 - 1

f (0) = - 1

f (x) = x^3 - 1 ... when x = 1

f (1) = 1^3 - 1

f (1) = 0

f (x) = x^3 - 1 ... when x = 2

f (2) = 2^3 - 1

f (2) = 8 - 1

f (2) = 7

so ur range f (x) = {0,-1,7} when ur domain (x) = {0,1,2}