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29 October, 00:37

Tickets to the fair cost $8 for children and $15 for adults on Thursday 177 people enter the fair and they collected $2053. what number of the children and what number of adults attended?

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  1. 29 October, 00:47
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    So,

    Let

    number of children tickets bought = c

    number of adult tickets bought = a

    We can now say that

    c + a = 177

    8c + 15a = 2053

    because if you multiply c by the cost per child and a by the cost per adult, you will get the total revenue generated by all the tickets.

    We now have a system of equations which can be solved by elimination (substitution).

    Subtract a from both sides of the first equation.

    c = 177 - a

    Substitute 177 - a for c in the second equation.

    8 (177 - a) + 15a = 2053

    Distribute.

    1416 - 8a + 15a = 2053

    Collect Like Terms.

    1416 + 7a = 2053

    Subtract 1416 from both sides.

    7a = 637

    Divide both sides by 7.

    a = 91

    Substitute 91 for a in the first modified equation.

    c = 177 - 91

    c = 86

    Check.

    The total number of people was 86 + 91 = 177 people.

    The total revenue generated was 8 (86) + 15 (91) = 688 + 1365 = $2053.

    There were 86 children and 91 adults.
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