There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different ways are there to schedule the appearances?

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Mathematics

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3 May, 10:47

There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different ways are there to schedule the appearances?

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Judith Hess · Answer 1

Since there are 8 but the last comedian will always perform last the amount of comedians you have to take into account in 7. To calculate the amount of combinations use 7! which is 5040. So there are 5040 different ways the comedians could be scheduled.