The polynomial of degree 5, P (x) has leading coefficient 1, has roots of multiplicity 2 at x=3 and x=0, and a root of multiplicity 1 at x=-5

Question

Mathematics

Dixie Riddle

14 October, 22:34

The polynomial of degree 5, P (x) has leading coefficient 1, has roots of multiplicity 2 at x=3 and x=0, and a root of multiplicity 1 at x=-5

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Kaliyah Hendricks · Answer 1

It means P (x) = (x) (x) (x-3) (x-3) (x+5)

xx (x-3) (x-3) (x+5)

= (xx (x-3) (x-3)) (x+5)

= (xx (x-3) (x-3)) (x) + (xx (x-3) (x-3)) (5)

= x^5 - 6^ x4 + 9^ x3 + 5 x^4 - 30 x^3 + 45 x^2

= x^5 - x^4 - 21 x^3 + 45^ x 2