1. Which equation represents the axis of symmetry of the function y = - 2x² + 4x - 6?

y = 1

x = 1

x = 3

x = - 3

2. What are the coordinates of the vertex of the graph of the function y = - x² + 6x - 11?

(3, - 2)

(3, 16)

(-3, - 29)

(-3, - 20)

3. What are the coordinates of the vertex of the graph of the function y = - 3x² - 12x + 3?

(-2, 29)

(2, - 15)

(2, - 9)

(-2, 15)

1 - of the function y=-2x^2+4x-6?

You gave no choices.

y=-2 (x^2-2x) - 6

y=-2 (x^2-2x+1) - 6+2

y=-2 (x-1) ² - 4

x=1

2 - x: use the same equation to find x, x = - (6) / 2 (-1) = - 6/-2=3 Then use that x in the original equation: y = - (3) ^2+6 (3) - 11=-2 Vertex is at (3,-2)

3 - coordinate of vertex

x = - b / 2 a

In this case:

x = - ( - 12) / [ 2 ( - 3) ] = 12 / - 6 = - 2

y - coordinate:

y = - 3 ( - 2) ^ 2 - 12 ( - 2) + 3 =

- 3 * 4 + 24 + 3 = - 12 + 24 + 3 = 15 so its D