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15 February, 20:21

For triangle ABC side a=19, side b=10, and angle A=141 find side c to the nearest whole number

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  1. 15 February, 23:06
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    Given the value of two sides and an angle to determine the value of the third side. Use Cosine Law:

    a^2 = c^2 + b^2 - 2bc*cosA

    a = 19

    b = 10

    A = 141 degrees

    19^2 = c^2 + 10^2 - (2*10*c*cos (141))

    solve for c
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