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6 April, 00:28

2cos theta = sec theta ... what are they asking me to find?

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Answers (2)
  1. 6 April, 01:47
    0
    2cos θ = sec θ = 1/cos θ

    2cos^2 θ = 1

    cos^2 θ = 1/2

    cos θ = sqrt (1/2)

    θ = arccos (sqrt (1/2)) = 45°

    θ = 45°
  2. 6 April, 03:47
    0
    Can you go more into the question can you analyze it better so i can get a better understanding for what the question is saying.
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