The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.

length = 1 yd, width = 20 yd

length = 2 yd, width = 10 yd

length = 10 yd, width = 2 yd

length = 20 yd, width = 1 y

Question

Mathematics

Rohan Benson

20 March, 17:52

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.

length = 1 yd, width = 20 yd

length = 2 yd, width = 10 yd

length = 10 yd, width = 2 yd

length = 20 yd, width = 1 y

+4

Answers (1)

Know the Answer?

Harley Little · Answer 1

The answer is length = 10 yd, width = 2 yd

proof

The length of the playground is 5 times longer than its width, it means

l=5w, but 10 = 2x5 so we can write l = 5w,

and Area = 20 = l x w = (5x2) x 2 = 20

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.length = 1 yd, width = 20 ydlength = 2 yd, width = 10 ydlength = 10 yd, width = 2 ydlength = 20 yd, width = 1 y

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.

length = 1 yd, width = 20 yd

length = 2 yd, width = 10 yd

length = 10 yd, width = 2 yd

length = 20 yd, width = 1 y