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27 August, 06:04

A spherical gemstone just fits inside a plastic cube with edges 12cm. a) calculate the volume of gemstone, to the nearest cubic centimeter. b) how much empty space is there.

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  1. 27 August, 07:23
    0
    a) (V) = 904.78 of a sphere = 288pi diameter = 12

    (V) = 1728cm^3 of a cube = face diagonal = 16.9cm

    b) Difference Volume = 1728-904.78 = 823.22cm^3

    Step-by-step explanation:

    To find volume of an inscribed sphere within a square cube

    We use 4 π/3 * r^3 for the equation

    As Radius = 6 = 6cm this is the only thing plugged into the equation to create a division first then a multiplication square of radius and then a multiplication. 4pi / 3 * 6^3

    r^3 = 216

    4pi/3 = 4.18

    4.18 * 216 = 904.78

    This means the answer is 288 pi cm^3.
  2. 27 August, 09:48
    0
    volume of gemstone = 905 cm^3

    volume of empty space = 823 cm^3

    Step-by-step explanation:

    volume of cube = s^3, where s = length of edge

    volume of sphere = (4/3) (pi) r^3, where r = radius of sphere

    The cube has a 12-cm edge. The sphere fits tightly inside the cube, so the diameter, d, of the sphere is 12 cm. The radius is half the diameter, so radius = r = diameter/2 = 12 cm/2 = 6 cm.

    a)

    volume of sphere = (4/3) (pi) r^3

    volume of sphere = (4/3) (3.14159) (6 cm) ^3

    volume of sphere = 905 cm^3

    b)

    The empty space is the difference between the volume of the cube and the volume of the sphere.

    volume of cube = s^3

    volume of cube = (12 cm) ^3

    volume of cube = 1728 cm^3

    empty space = volume of cube - volume of sphere

    empty space = 1728 cm^3 - 905 cm^3

    empty space = 823 cm^3
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