at is another way to write the expression p⋅ (10-2) ? (10⋅2) - p 10⋅2-p (10⋅2) ⋅p (p⋅10) - (p⋅2)

(p ⋅ 10) - (p ⋅ 2)

Step-by-step explanation:

Try to substitute "p" with any number.

Let's say p = 2

So

p ⋅ (10 - 2)

2 ⋅ (10 - 2)

2 ⋅ (8)

= 16

Now for the other equations

(p ⋅ 10) - (p ⋅ 2)

(2 ⋅ 10) - (2 ⋅ 2)

(20) - (4)

= 16

(10 ⋅ 2) - p

(10 ⋅ 2) - 2

(20) - 2

= 18

10 ⋅ 2 - p

10 ⋅ 2 - 2

20 - 2

= 18

(10 ⋅ 2) ⋅ p

(10 ⋅ 2) ⋅ 2

(20) ⋅ 2

= 40

Only (p ⋅ 10) - (p ⋅ 2) has the same result as p ⋅ (10 - 2).

Cheers