Ask Question
5 May, 09:16

A bag contains 3 red marbles, 2 blue marbles, and 5 green marbles. What is the probability of selecting a red marble, replacing it in the bad and then selecting a green marble

+1
Answers (1)
  1. 5 May, 12:15
    0
    3/20

    Step-by-step explanation:

    The total number of marbles is

    3 red marbles + 2 blue marbles + 5 green marbles = 10 marbles

    P (1st marble is red) = red marbles/total

    =3/10

    We replace the marble so there are still 10 marbles in the bag

    P (2nd marble is green) = green marbles/total

    =5/10 = 1/2

    P (1st red, 2nd green) = P (1st marble is red) * P (2nd marble is green)

    =3/10 * 1/2

    =3/20
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A bag contains 3 red marbles, 2 blue marbles, and 5 green marbles. What is the probability of selecting a red marble, replacing it in the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers