Find two consecutive even integers such that eight times the first equals seven times the second equals

Hence two consecutive even integers are 14 and 16

Step-by-step explanation:

Let x and x+2 be the two consecutive even integers

Then according to the given statement in the question

8x = 7 (x+2)

Distributive property

8x=7x+14

Subtraction Property of Equality

8x-7x = 14+7x-7x

Simplifying

x = 14

So the first integer is 14 and second is:

x+2 = 14+2 = 16

Hence two consecutive even integers are 14 and 16 ...