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4 January, 06:05

Yun wants to build a one-sample z interval with 82%, percent confidence to estimate what proportion of users will click an advertisement that appears on his website. He takes a random sample of 200 users and finds that 34 of them clicked the advertisement.

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  1. 4 January, 09:22
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    Step-by-step explanation:

    Confidence interval is written as

    Sample proportion ± margin of error

    Margin of error = z * √pq/n

    Where

    z represents the z score corresponding to the confidence level

    p = sample proportion. It also means probability of success

    q = probability of failure

    q = 1 - p

    p = x/n

    Where

    n represents the number of samples

    x represents the number of success

    From the information given,

    n = 200

    x = 34

    p = 34/200 = 0.17

    q = 1 - 0.17 = 0.83

    To determine the z score, we subtract the confidence level from 100% to get α

    α = 1 - 0.82 = 0.18

    α/2 = 0.18/2 = 0.09

    This is the area in each tail. Since we want the area in the middle, it becomes

    1 - 0.09 = 0.91

    The z score corresponding to the area on the z table is 1.35. Thus, the z score for a confidence level of 82% is 1.35

    Therefore, the 82% confidence interval is

    0.17 ± 1.35√ (0.17) (0.83) / 200

    Confidence interval is 0.17 ± 0.036
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