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26 July, 11:34

There are 26 cards in a hat, each of them containing a different letter of the alphabet. If one card is chosen at random, what is the probability that it is not between the letters L and P, inclusive

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  1. 26 July, 14:15
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    0.81

    Step-by-step explanation:

    The letters between L and P are M, N, O.

    It is inclusive, so we have 5 letters L, M, N, O, P.

    The letters which we can choose we have 26-5=21.

    The probability to choose a letter not between L and P is 21/26=0.81

    The solution is 0.81, ie,

    You have 81% chance to choose latter not between L and P.
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