Find three consecutive odd integers with the sum of 63

19, 21, 23

Step-by-step explanation:

Let x be the first integer.

Let x + 2 be the second integer.

Let x + 4 be the third integer.

The sum of the three consecutive odd integers is 63, so your equation is:

(x) + (x+2) + (x+4) = 63

Then solve for x

(x) + (x+2) + (x+4) = 63

x + x+2 + x+4 = 63

3x + 6 = 63

3x + 6 - 6 = 63 - 6

3x = 57

3x : 3 = 57 : 3

x = 19

Now that you know your first integer has a value of

19, substitute x = 19 into x + 2 and x + 4

to find the values of the second and third integers.

x + 2 x + 4

= (19 + 2) = (19 + 4)

= 21 = 23

We have to set up a simple equation here. n + (n+2) + (n+4) = 63. Now we solve. 3n+6=63, so 3n=57. n=19. n=19, n+2=21, and n+4=23. So the consecutive integers are, in order, 19, 21 and 23.