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4 March, 19:09

If sin theta = - (sqrt (3)) / 2 and pi < = theta < = (3pi) / 2, determine the value of cos (20)

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  1. 4 March, 19:43
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    Sin theta = - 1/2

    Step-by-step explanation:

    pi < = theta < = (3pi) / 2.

    The above expression shows we are dealing with angle on the 3rd quadrant.

    I. e greater than 180 but less than 270.

    So sin tita = (√3) / 2

    But sin and cos are all negative in the third quadrant.

    So tita = sin^-1 (√3) / 2

    tita = 60°

    Cos tita = cos 60

    Cos tita = cos 60

    Cos60 = 0.5

    Cos 60 = 1/2

    If

    sin theta = - (sqrt (3)) / 2

    Sin theta = - 1/2
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