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22 June, 00:02

What is the 6th term of the geometric sequence below?

2, 4, 8, 16, ...

A 24

B 32

C 64

D 18

Answers (2)
  1. M
    22 June, 02:47
    0
    C. 64.

    Step-by-step explanation:

    The nth term = a1 r^ (n-1) where a1 = first term and r = common ratio.

    Here a1 = 2 and common ratio r = 4/2 = 2.

    6th term = 2 (2) ^ (6-1)

    = 2 * 2^5

    = 2*32

    = 64.
  2. B
    22 June, 03:17
    0
    C 64

    Step-by-step explanation:

    We are multiplying by 2 each time

    1st term is 2

    2*2 = 4

    2nd term is 4

    4*2 = 8

    3rd term is 8

    8*2 = 16

    4th term is 16

    16*2=32

    5th term is 32

    32*2=64

    6th term is 64
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