What percent of team B's mean absolute deviation is the difference in the means?

The difference between the mean time is about 16 times the mean absolute deviation of the data sets.

Step-by-step explanation:

We know the mean and absolute mean deviation of two team in a tables as:

Team A Team B

Mean 127.9s 127.4s

Mean absolute deviation 0.26s 0.23s

The difference of mean between two team A and B = 0.5 s

Also,

The difference of mean absolute deviation = 0.03 s

Now, let the difference of the mean times be equal to n times the difference of the mean absolute deviation of two teams.

0.5 = n x 0.03

n = 16.667 (Approx 16)

Therefore, the difference between the mean time is about the 16 times the absolute deviation of the data sets.