12. Suppose that a combination lock is opened by entering a three-digit code. Each digit can be any integer between 0 and 9, but digits may not be repeated in the code. How many

different codes are possible? Is this question answered by considering permutations or combinations? Explain.

Question

Mathematics

Taniya Henderson

27 January, 06:22

12. Suppose that a combination lock is opened by entering a three-digit code. Each digit can be any integer between 0 and 9, but digits may not be repeated in the code. How many

different codes are possible? Is this question answered by considering permutations or combinations? Explain.

+3

Answers (1)

Know the Answer?

Frances Sanchez · Answer 1

Answer:120

Step-by-step explanation:

from 0 - 9, we have 10 alphabets.

nCr = n! / (n-r) ! r!

10C3 = 10! / (10-3!) 3!

=10 * 9*8*7! / 7!3!

=10*9*8 / 6

=720/6

=120

The answe to the second part of the question:

The question is answered considering combination because in the arrangement of the digit, order doesn't matter in the arrangement.

12. Suppose that a combination lock is opened by entering a three-digit code. Each digit can be any integer between 0 and 9, but digits may not be repeated in the code. How manydifferent codes are possible? Is this question answered by considering permutations or combinations? Explain.

12. Suppose that a combination lock is opened by entering a three-digit code. Each digit can be any integer between 0 and 9, but digits may not be repeated in the code. How many

different codes are possible? Is this question answered by considering permutations or combinations? Explain.