Identify the distance, to the nearest tenth, between C (-7,-9) and J (6,2).

The answer is 17.02, to the nearest tenth is 17.

Step-by-step explanation:

Under the radical, that us take the square root of the following sum:

(Jx - Cx) ^2 + (Jy - Cy) ^2

Substitute in the values:

(6 - (-7)) ^2 + (2 - (-9)) ^2 =

This becomes:

(6+7) ^2 + (2 + 9) ^2 =

13^2 + 11^2 =

169 + 121 =

Sqrt 290 =

17.029 = To the nearest 10th is 17