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13 October, 04:02

In how many ways can 4 different novels, 2 different mathematics books, and 1 biology book be arranged on a bookshelf if the novels must be together but the other books can be arranged in any order?

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  1. 13 October, 05:18
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    Pt = 576

    Step-by-step explanation:

    If 4 different novels must be together, we have 4 elements then

    P₁ = 4! P₁ = 4*3*2*1

    P₁ = 24

    But now we have to consider position between the novel group

    P₂ = 4! P₂ = 24

    Total ways

    Pt = 24*24

    Pt = 576
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