In how many ways can 4 different novels, 2 different mathematics books, and 1 biology book be arranged on a bookshelf if the novels must be together but the other books can be arranged in any order?

Pt = 576

Step-by-step explanation:

If 4 different novels must be together, we have 4 elements then

P₁ = 4! P₁ = 4*3*2*1

P₁ = 24

But now we have to consider position between the novel group

P₂ = 4! P₂ = 24

Total ways

Pt = 24*24

Pt = 576